10x2+23x-42=0

Solution for 10x2+23x-42=0 equation:

10x^2+23x-42=0

a = 10; b = 23; c = -42;
Δ = b2-4ac
Δ = 232-4·10·(-42)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-47}{2*10}=\frac{-70}{20}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+47}{2*10}=\frac{24}{20}
=1+1/5
$