10x2+26x-3=x2

Solution for 10x2+26x-3=x2 equation:

10x^2+26x-3=x2

We move all terms to the left:

10x^2+26x-3-(x2)=0

We add all the numbers together, and all the variables

9x^2+26x-3=0

a = 9; b = 26; c = -3;
Δ = b2-4ac
Δ = 262-4·9·(-3)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-28}{2*9}=\frac{-54}{18}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+28}{2*9}=\frac{2}{18}
=1/9
$