10x2+27x-28=0

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Solution for 10x2+27x-28=0 equation:



10x^2+27x-28=0
a = 10; b = 27; c = -28;
Δ = b2-4ac
Δ = 272-4·10·(-28)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-43}{2*10}=\frac{-70}{20} =-3+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+43}{2*10}=\frac{16}{20} =4/5 $

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