10x2+30x+3=0

Solution for 10x2+30x+3=0 equation:

10x^2+30x+3=0

a = 10; b = 30; c = +3;
Δ = b2-4ac
Δ = 302-4·10·3
Δ = 780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{780}=\sqrt{4*195}=\sqrt{4}*\sqrt{195}=2\sqrt{195}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{195}}{2*10}=\frac{-30-2\sqrt{195}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{195}}{2*10}=\frac{-30+2\sqrt{195}}{20}
$