10x2+60x=800

Solution for 10x2+60x=800 equation:

10x^2+60x=800

We move all terms to the left:

10x^2+60x-(800)=0

a = 10; b = 60; c = -800;
Δ = b2-4ac
Δ = 602-4·10·(-800)
Δ = 35600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{35600}=\sqrt{400*89}=\sqrt{400}*\sqrt{89}=20\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20\sqrt{89}}{2*10}=\frac{-60-20\sqrt{89}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20\sqrt{89}}{2*10}=\frac{-60+20\sqrt{89}}{20}
$