10x2+61x+90=0

Solution for 10x2+61x+90=0 equation:

10x^2+61x+90=0

a = 10; b = 61; c = +90;
Δ = b2-4ac
Δ = 612-4·10·90
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-11}{2*10}=\frac{-72}{20}
=-3+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+11}{2*10}=\frac{-50}{20}
=-2+1/2
$