10x2+67x-42=0

Solution for 10x2+67x-42=0 equation:

10x^2+67x-42=0

a = 10; b = 67; c = -42;
Δ = b2-4ac
Δ = 672-4·10·(-42)
Δ = 6169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-\sqrt{6169}}{2*10}=\frac{-67-\sqrt{6169}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+\sqrt{6169}}{2*10}=\frac{-67+\sqrt{6169}}{20}
$