10x2+6x-13=0

Solution for 10x2+6x-13=0 equation:

10x^2+6x-13=0

a = 10; b = 6; c = -13;
Δ = b2-4ac
Δ = 62-4·10·(-13)
Δ = 556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{556}=\sqrt{4*139}=\sqrt{4}*\sqrt{139}=2\sqrt{139}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{139}}{2*10}=\frac{-6-2\sqrt{139}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{139}}{2*10}=\frac{-6+2\sqrt{139}}{20}
$