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10x^2+7x+9=8
We move all terms to the left:
10x^2+7x+9-(8)=0
We add all the numbers together, and all the variables
10x^2+7x+1=0
a = 10; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·10·1
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*10}=\frac{-10}{20} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*10}=\frac{-4}{20} =-1/5 $
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