10x2+7x=6

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Solution for 10x2+7x=6 equation:



10x^2+7x=6
We move all terms to the left:
10x^2+7x-(6)=0
a = 10; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·10·(-6)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*10}=\frac{-24}{20} =-1+1/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*10}=\frac{10}{20} =1/2 $

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