10x2+8=158

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Solution for 10x2+8=158 equation:



10x^2+8=158
We move all terms to the left:
10x^2+8-(158)=0
We add all the numbers together, and all the variables
10x^2-150=0
a = 10; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·10·(-150)
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*10}=\frac{0-20\sqrt{15}}{20} =-\frac{20\sqrt{15}}{20} =-\sqrt{15} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*10}=\frac{0+20\sqrt{15}}{20} =\frac{20\sqrt{15}}{20} =\sqrt{15} $

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