10x2+9x-7=0

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Solution for 10x2+9x-7=0 equation:



10x^2+9x-7=0
a = 10; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·10·(-7)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-19}{2*10}=\frac{-28}{20} =-1+2/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+19}{2*10}=\frac{10}{20} =1/2 $

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