If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2+x+10=0
a = 10; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·10·10
Δ = -399
Delta is less than zero, so there is no solution for the equation
| 5x+3(x+5)=2(x+8) | | -7=-3+w | | 3.5m-1=6 | | 8x+12-4x=16 | | 4x-2-2x=-5 | | 9q2+6=0 | | 12(x-7)=-40.8 | | 5r2–6=0 | | (5x+29)=(9x-15) | | 9w=-6w2–1 | | 4x+9=x+1 | | 8v2+8=0 | | 321-x=250 | | 4p2+5=0 | | 5(6x+2)+1=101 | | 3r2–2r+1=0 | | 7q2+4q+1=0 | | 8r2+9=0 | | 10=(5/6)x | | x^2+10x-57=0 | | 7t2+t=0 | | y2–8=0 | | 10-0.5x=(1/3)x | | v2–6v+1=0 | | 10-0.5x=1/3x | | 6=-6+4w | | 7w2–7w–8=0 | | 9z2+4z+5=0 | | 13x-2(3x-4)=1 | | 2u2–3u–3=0 | | 9r2+8r+5=0 | | Y=72,x=3 |