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10x^2-101x+136=0
a = 10; b = -101; c = +136;
Δ = b2-4ac
Δ = -1012-4·10·136
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-101)-69}{2*10}=\frac{32}{20} =1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-101)+69}{2*10}=\frac{170}{20} =8+1/2 $
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