If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10x^2-13x-13=0
a = 10; b = -13; c = -13;
Δ = b2-4ac
Δ = -132-4·10·(-13)
Δ = 689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{689}}{2*10}=\frac{13-\sqrt{689}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{689}}{2*10}=\frac{13+\sqrt{689}}{20} $
| 4x2+13x-10=0 | | 8p+13p-4p=153 | | 8.7=4u-4.1 | | 73+9x+8=90 | | (2x-3)(130)=180 | | 7x+70=360 | | -1-3b=-4 | | 2(3x-5)-7=1 | | 5x18=-4x | | 5(3x+4)=4(x+6) | | -18x=1 | | 3x-5=16-x | | -5x22=-67 | | 118-x=96 | | 1/2x+12-60=-0.5x-60+3x | | 140=176-8x | | 2x+28.5=180 | | 12t+6t-7t=3t-2t | | 12=6t-7t=3t-2t | | 5=800-18w | | 476=800-18w | | x+46=64 | | (4)9=x+50 | | 2(x+5)=-4x-26 | | 6w-32=4(w-9) | | 8y+7(7+y)=34 | | 4x+1=1x+9 | | 2*x+4*(x-3)=5*(x-1)-9 | | 5*x+1=-2*(3+x) | | x-19-3*(x-2)=3*(4-x) | | 3*(2-3*x)=6 | | 3*y=15-7*(y+3) |