10x2-16x-12=0

Solution for 10x2-16x-12=0 equation:

10x^2-16x-12=0

a = 10; b = -16; c = -12;
Δ = b2-4ac
Δ = -162-4·10·(-12)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{46}}{2*10}=\frac{16-4\sqrt{46}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{46}}{2*10}=\frac{16+4\sqrt{46}}{20}
$