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10x^2-20=180
We move all terms to the left:
10x^2-20-(180)=0
We add all the numbers together, and all the variables
10x^2-200=0
a = 10; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·10·(-200)
Δ = 8000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8000}=\sqrt{1600*5}=\sqrt{1600}*\sqrt{5}=40\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{5}}{2*10}=\frac{0-40\sqrt{5}}{20} =-\frac{40\sqrt{5}}{20} =-2\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{5}}{2*10}=\frac{0+40\sqrt{5}}{20} =\frac{40\sqrt{5}}{20} =2\sqrt{5} $
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