10x2-20x-180=0

Solution for 10x2-20x-180=0 equation:

10x^2-20x-180=0

a = 10; b = -20; c = -180;
Δ = b2-4ac
Δ = -202-4·10·(-180)
Δ = 7600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7600}=\sqrt{400*19}=\sqrt{400}*\sqrt{19}=20\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{19}}{2*10}=\frac{20-20\sqrt{19}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{19}}{2*10}=\frac{20+20\sqrt{19}}{20}
$