10x2-21x+9=0

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Solution for 10x2-21x+9=0 equation:



10x^2-21x+9=0
a = 10; b = -21; c = +9;
Δ = b2-4ac
Δ = -212-4·10·9
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-9}{2*10}=\frac{12}{20} =3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+9}{2*10}=\frac{30}{20} =1+1/2 $

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