10x2-21x-10=0

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Solution for 10x2-21x-10=0 equation:



10x^2-21x-10=0
a = 10; b = -21; c = -10;
Δ = b2-4ac
Δ = -212-4·10·(-10)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-29}{2*10}=\frac{-8}{20} =-2/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+29}{2*10}=\frac{50}{20} =2+1/2 $

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