10x2-24x-6=0

Solution for 10x2-24x-6=0 equation:

10x^2-24x-6=0

a = 10; b = -24; c = -6;
Δ = b2-4ac
Δ = -242-4·10·(-6)
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{51}}{2*10}=\frac{24-4\sqrt{51}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{51}}{2*10}=\frac{24+4\sqrt{51}}{20}
$