10x2-35x-20=0

Solution for 10x2-35x-20=0 equation:

10x^2-35x-20=0

a = 10; b = -35; c = -20;
Δ = b2-4ac
Δ = -352-4·10·(-20)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-45}{2*10}=\frac{-10}{20}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+45}{2*10}=\frac{80}{20}
=4
$