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10x^2-35x-45=0
a = 10; b = -35; c = -45;
Δ = b2-4ac
Δ = -352-4·10·(-45)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-55}{2*10}=\frac{-20}{20} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+55}{2*10}=\frac{90}{20} =4+1/2 $
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