10x2-45x-450=0

Solution for 10x2-45x-450=0 equation:

10x^2-45x-450=0

a = 10; b = -45; c = -450;
Δ = b2-4ac
Δ = -452-4·10·(-450)
Δ = 20025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20025}=\sqrt{225*89}=\sqrt{225}*\sqrt{89}=15\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-15\sqrt{89}}{2*10}=\frac{45-15\sqrt{89}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+15\sqrt{89}}{2*10}=\frac{45+15\sqrt{89}}{20}
$