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10x^2-4=6
We move all terms to the left:
10x^2-4-(6)=0
We add all the numbers together, and all the variables
10x^2-10=0
a = 10; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·10·(-10)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*10}=\frac{-20}{20} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*10}=\frac{20}{20} =1 $
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