10x2-5x=x+2

Solution for 10x2-5x=x+2 equation:

10x^2-5x=x+2

We move all terms to the left:

10x^2-5x-(x+2)=0

We get rid of parentheses

10x^2-5x-x-2=0

We add all the numbers together, and all the variables

10x^2-6x-2=0

a = 10; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·10·(-2)
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{29}}{2*10}=\frac{6-2\sqrt{29}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{29}}{2*10}=\frac{6+2\sqrt{29}}{20}
$