10x2-6=9x

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Solution for 10x2-6=9x equation:



10x^2-6=9x
We move all terms to the left:
10x^2-6-(9x)=0
a = 10; b = -9; c = -6;
Δ = b2-4ac
Δ = -92-4·10·(-6)
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{321}}{2*10}=\frac{9-\sqrt{321}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{321}}{2*10}=\frac{9+\sqrt{321}}{20} $

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