10x2-7x-5=0

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Solution for 10x2-7x-5=0 equation:



10x^2-7x-5=0
a = 10; b = -7; c = -5;
Δ = b2-4ac
Δ = -72-4·10·(-5)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{249}}{2*10}=\frac{7-\sqrt{249}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{249}}{2*10}=\frac{7+\sqrt{249}}{20} $

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