10x2-80=2x2+320

Solution for 10x2-80=2x2+320 equation:

10x^2-80=2x^2+320

We move all terms to the left:

10x^2-80-(2x^2+320)=0

We get rid of parentheses

10x^2-2x^2-320-80=0

We add all the numbers together, and all the variables

8x^2-400=0

a = 8; b = 0; c = -400;
Δ = b2-4ac
Δ = 02-4·8·(-400)
Δ = 12800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12800}=\sqrt{6400*2}=\sqrt{6400}*\sqrt{2}=80\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{2}}{2*8}=\frac{0-80\sqrt{2}}{16}
=-\frac{80\sqrt{2}}{16}
=-5\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{2}}{2*8}=\frac{0+80\sqrt{2}}{16}
=\frac{80\sqrt{2}}{16}
=5\sqrt{2}
$