10x2-8=(x+1)

Solution for 10x2-8=(x+1) equation:

10x^2-8=(x+1)

We move all terms to the left:

10x^2-8-((x+1))=0


We calculate terms in parentheses: -((x+1)), so:

(x+1)

We get rid of parentheses

x+1

Back to the equation:

-(x+1)


We get rid of parentheses

10x^2-x-1-8=0

We add all the numbers together, and all the variables

10x^2-1x-9=0

a = 10; b = -1; c = -9;
Δ = b2-4ac
Δ = -12-4·10·(-9)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-19}{2*10}=\frac{-18}{20}
=-9/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+19}{2*10}=\frac{20}{20}
=1
$