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10x^2-90x+225=45
We move all terms to the left:
10x^2-90x+225-(45)=0
We add all the numbers together, and all the variables
10x^2-90x+180=0
a = 10; b = -90; c = +180;
Δ = b2-4ac
Δ = -902-4·10·180
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-30}{2*10}=\frac{60}{20} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+30}{2*10}=\frac{120}{20} =6 $
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