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10x^2/7x-4=3
We move all terms to the left:
10x^2/7x-4-(3)=0
Domain of the equation: 7x!=0We add all the numbers together, and all the variables
x!=0/7
x!=0
x∈R
10x^2/7x-7=0
We multiply all the terms by the denominator
10x^2-7*7x=0
Wy multiply elements
10x^2-49x=0
a = 10; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·10·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*10}=\frac{0}{20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*10}=\frac{98}{20} =4+9/10 $
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