10x2=1-5x

Solution for 10x2=1-5x equation:

10x^2=1-5x

We move all terms to the left:

10x^2-(1-5x)=0

We add all the numbers together, and all the variables

10x^2-(-5x+1)=0

We get rid of parentheses

10x^2+5x-1=0

a = 10; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·10·(-1)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{65}}{2*10}=\frac{-5-\sqrt{65}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{65}}{2*10}=\frac{-5+\sqrt{65}}{20}
$