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10x^2=2(6x+2)
We move all terms to the left:
10x^2-(2(6x+2))=0
We calculate terms in parentheses: -(2(6x+2)), so:We get rid of parentheses
2(6x+2)
We multiply parentheses
12x+4
Back to the equation:
-(12x+4)
10x^2-12x-4=0
a = 10; b = -12; c = -4;
Δ = b2-4ac
Δ = -122-4·10·(-4)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{19}}{2*10}=\frac{12-4\sqrt{19}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{19}}{2*10}=\frac{12+4\sqrt{19}}{20} $
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