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10x^2=24
We move all terms to the left:
10x^2-(24)=0
a = 10; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·10·(-24)
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{15}}{2*10}=\frac{0-8\sqrt{15}}{20} =-\frac{8\sqrt{15}}{20} =-\frac{2\sqrt{15}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{15}}{2*10}=\frac{0+8\sqrt{15}}{20} =\frac{8\sqrt{15}}{20} =\frac{2\sqrt{15}}{5} $
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