10x2=320

Solution for 10x2=320 equation:

10x^2=320

We move all terms to the left:

10x^2-(320)=0

a = 10; b = 0; c = -320;
Δ = b2-4ac
Δ = 02-4·10·(-320)
Δ = 12800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12800}=\sqrt{6400*2}=\sqrt{6400}*\sqrt{2}=80\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{2}}{2*10}=\frac{0-80\sqrt{2}}{20}
=-\frac{80\sqrt{2}}{20}
=-4\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{2}}{2*10}=\frac{0+80\sqrt{2}}{20}
=\frac{80\sqrt{2}}{20}
=4\sqrt{2}
$