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10x^2=72
We move all terms to the left:
10x^2-(72)=0
a = 10; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·10·(-72)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{5}}{2*10}=\frac{0-24\sqrt{5}}{20} =-\frac{24\sqrt{5}}{20} =-\frac{6\sqrt{5}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{5}}{2*10}=\frac{0+24\sqrt{5}}{20} =\frac{24\sqrt{5}}{20} =\frac{6\sqrt{5}}{5} $
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