10x2=9x+7

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Solution for 10x2=9x+7 equation:



10x^2=9x+7
We move all terms to the left:
10x^2-(9x+7)=0
We get rid of parentheses
10x^2-9x-7=0
a = 10; b = -9; c = -7;
Δ = b2-4ac
Δ = -92-4·10·(-7)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-19}{2*10}=\frac{-10}{20} =-1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+19}{2*10}=\frac{28}{20} =1+2/5 $

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