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10x=20/2x
We move all terms to the left:
10x-(20/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10x-(+20/2x)=0
We get rid of parentheses
10x-20/2x=0
We multiply all the terms by the denominator
10x*2x-20=0
Wy multiply elements
20x^2-20=0
a = 20; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·20·(-20)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*20}=\frac{-40}{40} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*20}=\frac{40}{40} =1 $
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