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10x=68-2(4-2x)=
We move all terms to the left:
10x-(68-2(4-2x))=0
We add all the numbers together, and all the variables
10x-(68-2(-2x+4))=0
We calculate terms in parentheses: -(68-2(-2x+4)), so:We get rid of parentheses
68-2(-2x+4)
determiningTheFunctionDomain -2(-2x+4)+68
We multiply parentheses
4x-8+68
We add all the numbers together, and all the variables
4x+60
Back to the equation:
-(4x+60)
10x-4x-60=0
We add all the numbers together, and all the variables
6x-60=0
We move all terms containing x to the left, all other terms to the right
6x=60
x=60/6
x=10
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