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10y*6y-4y=0
We add all the numbers together, and all the variables
-4y+10y*6y=0
Wy multiply elements
60y^2-4y=0
a = 60; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·60·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*60}=\frac{0}{120} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*60}=\frac{8}{120} =1/15 $
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