10y+15(3-2y)=-25-(-10y+5)

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Solution for 10y+15(3-2y)=-25-(-10y+5) equation:



10y+15(3-2y)=-25-(-10y+5)
We move all terms to the left:
10y+15(3-2y)-(-25-(-10y+5))=0
We add all the numbers together, and all the variables
10y+15(-2y+3)-(-25-(-10y+5))=0
We multiply parentheses
10y-30y-(-25-(-10y+5))+45=0
We calculate terms in parentheses: -(-25-(-10y+5)), so:
-25-(-10y+5)
determiningTheFunctionDomain -(-10y+5)-25
We get rid of parentheses
10y-5-25
We add all the numbers together, and all the variables
10y-30
Back to the equation:
-(10y-30)
We add all the numbers together, and all the variables
-20y-(10y-30)+45=0
We get rid of parentheses
-20y-10y+30+45=0
We add all the numbers together, and all the variables
-30y+75=0
We move all terms containing y to the left, all other terms to the right
-30y=-75
y=-75/-30
y=2+1/2

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