10y+35=5(2y+5)

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Solution for 10y+35=5(2y+5) equation: 



10y+35=5(2y+5)

We move all terms to the left:

10y+35-(5(2y+5))=0



We calculate terms in parentheses: -(5(2y+5)), so:

5(2y+5)

We multiply parentheses

10y+25

Back to the equation:

-(10y+25)



We get rid of parentheses

10y-10y-25+35=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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