10y+3y+(-19y)=18

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Solution for 10y+3y+(-19y)=18 equation: 



10y+3y+(-19y)=18

We move all terms to the left:

10y+3y+(-19y)-(18)=0

We add all the numbers together, and all the variables

13y+(-19y)-18=0

We get rid of parentheses

13y-19y-18=0

We add all the numbers together, and all the variables

-6y-18=0

We move all terms containing y to the left, all other terms to the right

-6y=18

y=18/-6

y=-3

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