10y-(4y+8)=2(y-5)+6

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Solution for 10y-(4y+8)=2(y-5)+6 equation:


Simplifying
10y + -1(4y + 8) = 2(y + -5) + 6

Reorder the terms:
10y + -1(8 + 4y) = 2(y + -5) + 6
10y + (8 * -1 + 4y * -1) = 2(y + -5) + 6
10y + (-8 + -4y) = 2(y + -5) + 6

Reorder the terms:
-8 + 10y + -4y = 2(y + -5) + 6

Combine like terms: 10y + -4y = 6y
-8 + 6y = 2(y + -5) + 6

Reorder the terms:
-8 + 6y = 2(-5 + y) + 6
-8 + 6y = (-5 * 2 + y * 2) + 6
-8 + 6y = (-10 + 2y) + 6

Reorder the terms:
-8 + 6y = -10 + 6 + 2y

Combine like terms: -10 + 6 = -4
-8 + 6y = -4 + 2y

Solving
-8 + 6y = -4 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-8 + 6y + -2y = -4 + 2y + -2y

Combine like terms: 6y + -2y = 4y
-8 + 4y = -4 + 2y + -2y

Combine like terms: 2y + -2y = 0
-8 + 4y = -4 + 0
-8 + 4y = -4

Add '8' to each side of the equation.
-8 + 8 + 4y = -4 + 8

Combine like terms: -8 + 8 = 0
0 + 4y = -4 + 8
4y = -4 + 8

Combine like terms: -4 + 8 = 4
4y = 4

Divide each side by '4'.
y = 1

Simplifying
y = 1

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