10y-1=2(4y-4)

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Solution for 10y-1=2(4y-4) equation: 



10y-1=2(4y-4)

We move all terms to the left:

10y-1-(2(4y-4))=0



We calculate terms in parentheses: -(2(4y-4)), so:

2(4y-4)

We multiply parentheses

8y-8

Back to the equation:

-(8y-8)



We get rid of parentheses

10y-8y+8-1=0

We add all the numbers together, and all the variables

2y+7=0

We move all terms containing y to the left, all other terms to the right

2y=-7

y=-7/2

y=-3+1/2

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