10y-2(1+y)=3(y-2)-20

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Solution for 10y-2(1+y)=3(y-2)-20 equation:


Simplifying
10y + -2(1 + y) = 3(y + -2) + -20
10y + (1 * -2 + y * -2) = 3(y + -2) + -20
10y + (-2 + -2y) = 3(y + -2) + -20

Reorder the terms:
-2 + 10y + -2y = 3(y + -2) + -20

Combine like terms: 10y + -2y = 8y
-2 + 8y = 3(y + -2) + -20

Reorder the terms:
-2 + 8y = 3(-2 + y) + -20
-2 + 8y = (-2 * 3 + y * 3) + -20
-2 + 8y = (-6 + 3y) + -20

Reorder the terms:
-2 + 8y = -6 + -20 + 3y

Combine like terms: -6 + -20 = -26
-2 + 8y = -26 + 3y

Solving
-2 + 8y = -26 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-2 + 8y + -3y = -26 + 3y + -3y

Combine like terms: 8y + -3y = 5y
-2 + 5y = -26 + 3y + -3y

Combine like terms: 3y + -3y = 0
-2 + 5y = -26 + 0
-2 + 5y = -26

Add '2' to each side of the equation.
-2 + 2 + 5y = -26 + 2

Combine like terms: -2 + 2 = 0
0 + 5y = -26 + 2
5y = -26 + 2

Combine like terms: -26 + 2 = -24
5y = -24

Divide each side by '5'.
y = -4.8

Simplifying
y = -4.8

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