10y-2-y=-2(2y+4)-3(2y-2)

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Solution for 10y-2-y=-2(2y+4)-3(2y-2) equation: 



10y-2-y=-2(2y+4)-3(2y-2)

We move all terms to the left:

10y-2-y-(-2(2y+4)-3(2y-2))=0

We add all the numbers together, and all the variables

9y-(-2(2y+4)-3(2y-2))-2=0



We calculate terms in parentheses: -(-2(2y+4)-3(2y-2)), so:

-2(2y+4)-3(2y-2)

We multiply parentheses

-4y-6y-8+6

We add all the numbers together, and all the variables

-10y-2

Back to the equation:

-(-10y-2)



We get rid of parentheses

9y+10y+2-2=0

We add all the numbers together, and all the variables

19y=0

y=0/19

y=0

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