10y-2-y=2(2y+4)-3(2y-2)

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Solution for 10y-2-y=2(2y+4)-3(2y-2) equation: 



10y-2-y=2(2y+4)-3(2y-2)

We move all terms to the left:

10y-2-y-(2(2y+4)-3(2y-2))=0

We add all the numbers together, and all the variables

9y-(2(2y+4)-3(2y-2))-2=0



We calculate terms in parentheses: -(2(2y+4)-3(2y-2)), so:

2(2y+4)-3(2y-2)

We multiply parentheses

4y-6y+8+6

We add all the numbers together, and all the variables

-2y+14

Back to the equation:

-(-2y+14)



We get rid of parentheses

9y+2y-14-2=0

We add all the numbers together, and all the variables

11y-16=0

We move all terms containing y to the left, all other terms to the right

11y=16

y=16/11

y=1+5/11

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