10y-4(y+2)=-20

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Solution for 10y-4(y+2)=-20 equation: 



10y-4(y+2)=-20

We move all terms to the left:

10y-4(y+2)-(-20)=0

We add all the numbers together, and all the variables

10y-4(y+2)+20=0

We multiply parentheses

10y-4y-8+20=0

We add all the numbers together, and all the variables

6y+12=0

We move all terms containing y to the left, all other terms to the right

6y=-12

y=-12/6

y=-2

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